x(1-c^2+4c)=7c-28

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Solution for x(1-c^2+4c)=7c-28 equation:


Simplifying
x(1 + -1c2 + 4c) = 7c + -28

Reorder the terms:
x(1 + 4c + -1c2) = 7c + -28
(1 * x + 4c * x + -1c2 * x) = 7c + -28

Reorder the terms:
(4cx + -1c2x + 1x) = 7c + -28
(4cx + -1c2x + 1x) = 7c + -28

Reorder the terms:
4cx + -1c2x + 1x = -28 + 7c

Solving
4cx + -1c2x + 1x = -28 + 7c

Solving for variable 'c'.

Reorder the terms:
28 + -7c + 4cx + -1c2x + 1x = -28 + 7c + 28 + -7c

Reorder the terms:
28 + -7c + 4cx + -1c2x + 1x = -28 + 28 + 7c + -7c

Combine like terms: -28 + 28 = 0
28 + -7c + 4cx + -1c2x + 1x = 0 + 7c + -7c
28 + -7c + 4cx + -1c2x + 1x = 7c + -7c

Combine like terms: 7c + -7c = 0
28 + -7c + 4cx + -1c2x + 1x = 0

The solution to this equation could not be determined.

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